2-4x^2/2-3x-x^2=50

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Solution for 2-4x^2/2-3x-x^2=50 equation: 


x in (-oo:+oo)

2-((4*x^2)/2)-x^2-(3*x) = 50 // - 50

2-((4*x^2)/2)-x^2-(3*x)-50 = 0

2-2*x^2-x^2-3*x-50 = 0

-3*x^2-3*x-48 = 0

DELTA = (-3)^2-(-48*(-3)*4)

DELTA = -567

DELTA < 0

x belongs to the empty set

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